A wire of resistance 4 is bent into a circle. The resistance between the ends of a diameter of the circle is:
Correct answer: B. 1 Ω
- A. 4Ω
- B. 1 Ω
- C. 1/4 Ω
- D. 1/16 Ω
Explanation
When a wire of resistance 4R is bent in the form of circle, then the resistance of each segment across the diameter becomes 2R.Equivalent resistance between A and B: +1/Rb (in parallel combination)∴ 1/RAB = 1/(2R) +1/(2R) 1/RAB = 2/(2R) ⟹ RAB=RHere is the link from where you understand this MCQ:
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