A current of 20.0A flows through a battery with an e.m.f of 6.20 V. If the internal resistance of the battery is 0.01, what is the terminal voltage?
Correct answer: D. 6.00V
- A. 6.40V
- B. 31.0V
- C. 1.24V
- D. 6.00V
Explanation
V = e.m.f - (I * Rinternal)where:V is the terminal voltage,e.m.f is the electromotive force (voltage) of the battery,I is the current flowing through the battery, andR_internal is the internal resistance of the battery.In this case, the e.m.f is given as 6.20 V, the current is 20.0 A, and the internal resistance is 0.01 Ω. Plugging these values into the formula, we get:V = 6.20 V - (20.0 A * 0.01 Ω)V = 6.20 V - 0.20 VV = 6.00 V
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Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
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