A string of n parallel SCRs is operated at 72 KA, the rating of each SCR is 1 KA. If derating factor of the string is 0.1. value of n will be___________?
Correct answer: C. 80
- A. 60
- B. 70
- C. 80
- D. 90
Explanation
With a 0.1 derating factor, only 90% of the parallel string capacity is usable. Thus, n × 1 × 0.9 = 72, giving n = 80 SCRs.
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