A square plate of 0.1 m side moves parallel to a second plate with a velocity of 0.1 m/s, both plates being immersed in water. If the viscous force is 0.002 N and the coefficient of viscosity is 0.01 poise distance between the plates in m is
Correct answer: D. 0.0005
- A. 0.1
- B. 0.05
- C. 0.005
- D. 0.0005
Explanation
The correct answer is option D:0.0005. The distance between the plates can be calculated using the formula for viscous force: F = eta * A × (v1 - v2) / d. Plugging in the given values of viscous force (0.002 N) and coefficient of viscosity (0.01 poise), along with the area of the square plate (0.1 m * 0.1 m), and the velocity (0.1 m/s), you can solve for the distance between the plates to be 0.0005 meters. The other options do not accurately represent the correct calculation of the distance between the plates.
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