A solenoid 15.0 cm long has 300 turns of wire, and a current of 5 A flows through it. The magnitude of magnetic field inside the solenoid is:
Correct answer: D. 1.37 x 10^-2 W/m2
- A. 1.37 x 10^-7 W/m2
- B. 1.37 x 10^-5 W/m2
- C. 1.37 x 10^-1 W/m2
- D. 1.37 x 10^-2 W/m2
Explanation
Given: Length = L = 15 cm = 0.15 m Number of turns = N = 300 Current = I = 5 APermittivity of free space = μo = 4π × 10-7 Magnetic field =?Solution: Turns per unit length = n = 300 / 0.15 = 2000 turns per meterAs we know that: B = μonl = 4π × 10-7 × 2000 × 5 = 1.37 × 10-2 W/m²
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