A metal rod of length 4 m, velocity 5 m/s, and magnetic field 0.5 T, induced emf is:
Correct answer: A. 10V
- A. 10V
- B. 20V
- C. 30V
- D. 4V
Explanation
The induced emf (ε) in a conductor moving at a velocity (v) perpendicular to a magnetic field (B) is given by the equation:ε = Bvlwhere l is the length of the conductor.Given:Length of the metal rod (l) = 4 mVelocity of the metal rod (v) = 5 m/sMagnetic field (B) = 0.5 TSubstituting the values in the equation, we get:ε = Bvl= 0.5 × 5 × 4= 10 VTherefore, the induced emf in the metal rod is 10 V
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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