Moderate

A small square loop of wire of side l is placed inside a large square loop of wire of side L(>>l ). The loops are coplanar and their centres coincide. The mutual inductance of the system is:

Correct answer: A. Directly proportional to I2

  • A. Directly proportional to I2
  • B. Inversely proportional to I2
  • C. Directly proportional L2
  • D. Inversely proportional to L2

Explanation

Because of larger loop, the field at the centre will beB = (4 × μ₀ i) / (4π (L/2)) (sin 45° + sin 45°)B = (μ₀ / 4π) (8√2 i / L)So, flux linked with the smaller loopφ₂ = B S₂ = (μ₀ / 4π) (8√2 / L) i l²φ₂ = M i₁Or M i = (μ₀ / 4π) (8√2 / L) i l²Or M = (μ₀ / 4π) (8√2 l² / L)Or M ∝ l²

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