A small square loop of wire of side l is placed inside a large square loop of wire of side L(>>l ). The loops are coplanar and their centres coincide. The mutual inductance of the system is:
Correct answer: A. Directly proportional to I2
- A. Directly proportional to I2
- B. Inversely proportional to I2
- C. Directly proportional L2
- D. Inversely proportional to L2
Explanation
Because of larger loop, the field at the centre will beB = (4 × μ₀ i) / (4π (L/2)) (sin 45° + sin 45°)B = (μ₀ / 4π) (8√2 i / L)So, flux linked with the smaller loopφ₂ = B S₂ = (μ₀ / 4π) (8√2 / L) i l²φ₂ = M i₁Or M i = (μ₀ / 4π) (8√2 / L) i l²Or M = (μ₀ / 4π) (8√2 l² / L)Or M ∝ l²
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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