A current I = 10 sin(100π t) amp. is passed in first coil, which induces a maximum e.m.f of 5π volt in second coil. The mutual inductance between the coils is:
Correct answer: D. 5 mH
- A. 10 mH
- B. 15 mH
- C. 25 mH
- D. 5 mH
Explanation
Let I = I₀ sin ωt,where I₀ = 10, ω = 100 πthen ε = M dI/dt= M d/dt (I₀ sin ωt)= M I₀ ω cos ωt∴ εₘₐₓ = M I₀ ω5π = M × 10 × 100 πM = 5 mH.
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