Moderate
A sample of 60Co27 has an initial activity of 20 μCi. After 5.27 years(half. life of 60Co27 ), the activity is:
Correct answer: B. 10 μCi
- A. 5 μCi
- B. 10 μCi
- C. 15 μCi
- D. 20 μCi
Explanation
After one half. life, activity A = A × (1/2) = 20 × 1/2 = 10 μCi.
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