A nucleus undergoes beta-minus decay: 14C6→ 14N7+ e-1. The Q. value is 0.156 MeV. The reaction is:
Correct answer: B. Exothermic
- A. Endothermic
- B. Exothermic
- C. Neutral
- D. Forbidden
Explanation
A positive Q. value (0.156 MeV) indicates energy is released, making the reaction exothermic.
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