A proton has mass m and charge q. It is suspended in electric and gravitational field. What is the magnitude of electric field?
Correct answer: A. E = m*g/ q
- A. E = m*g/ q
- B. E = m*g/ q*v
- C. E = m*g/ q*v*B
- D. E = q / m*g
Explanation
The formula for Electric Field is given by;E = F/qWhere, according to Newton's second law of motion, F = maE = ma/qIn the problem, the proton is suspended in a gravitational field, where F = W = mg, and accelerationbecomes acceleration due to gravity 'g'we get,E = mg/q
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About Electric Field Intensity
Electric field intensity is the force acting per unit positive test charge, with direction set by the force on that charge. Work includes fields of point charges, vector superposition, field lines and the relation between field and electric potential. Field intensity must be distinguished from electric force and potential.
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