A particle of mass 'm' is moving on a circular path of radius 'r' with velocity 'v', then centripetal force acting on it is F. if the velocity of particle increases by 2 times and radius of circular path increases by 4 times then new centripetal force F' will be;
Correct answer: D. F' = F
- A. F' = 2F
- B. F' = 1/2 * F
- C. F' = 4F
- D. F' = F
Explanation
Despite both the velocity and the radius changing, the net effect on the centripetal force remains the same. The increase in velocity and the increase in radius cancel each other out in such a way that the force does not change.
This question appeared on the UHS MDCAT 2024 paper, which you can sit online with every answer explained.
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About Angular and Linear Quantities
Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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