A fighter plane is moving in a vertical circle of radius r. Its minimum velocity at the highest point of the circle will be?
Correct answer: C. √gr
- A. √3gr
- B. √2gr
- C. √gr
- D. √(gr/2)
Explanation
At the highest point, the centripetal force is provided by the vertical component of the plane's weight, given by: Fc = mg Equating this to the centripetal force formula: mv²/r = mg Cancelling the mass and rearranging the equation: v² = gr Taking the square root of both sides: v = √gr Therefore, the minimum velocity at the highest point of the vertical circle is √gr.
This question appeared on the UHS MDCAT 2022 paper, which you can sit online with every answer explained.
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Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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