A 1000 kg vehicle is turning around a corner at 10 m/s as it travels along an arc of a circle. If the radius of the circular path is 10 m, how large a force must be exerted by the pavement on the tires to hold the vehicle in the circular path?
Correct answer: A. 1.0 x 10⁴ N
- A. 1.0 x 10⁴ N
- B. 3.0 x 10⁴ N
- C. 5.0 x 10⁴ N
- D. 7.0 x 10⁴ N
- E. 9.0 x 10⁴ N
Explanation
Given: mass = 1000kgvelocity = 10m/s radius = 10 mFind: F(centripetal force)=? Formula:F= mv²/r F= 1000×10²/10F= 10000F = 1×10⁴N
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