A 800 kg car is turning round a corner at 6 m/sec as it travels along an arc of circle of radius 12 m. The magnitude of force exerted by pavement on the tyres to hold the car in circular path is _.
Correct answer: A. 2400 N
- A. 2400 N
- B. 1200 N
- C. 400 N
- D. 4800 N
Explanation
The formula for the centripetal force will be used here, which is: F=mv2/r Where m is the mass, v is the velocity and r is the radius. F=(800)(6)2/12 Solve the right-hand side of the equation to obtain: F=2400N
Last updated
Related questions
A 1000 kg vehicle is turning around a corner at 10 m/s as it travels along an arc of a circle. If the radius of the circular path is 10 m, how large a force must be exerted by the pavement on the tires to hold the vehicle in the circular path?
A 400 gram ball is tied to the end of a cord and whirled in à horizontal circle of radius 0.6 m. If the ball makes five complete revolutions in 2 s, what is the ball's linear speed?
A 500 kg car takes a round turn of radius 50 m with a velocity of 36 km/hr. :The centripetal force is
A ball of mass 0.25kg attached to the end of a string of length 1.96m is moving in a horizontal circle. The string will break if the tension is more than 25N. What is the maximum speed at which the ball can be moved?
A ball of mass 0.25kg attached to the end of a string of length 1.96m is moving in a horzontal circle. The string will break if the tension is more than 25N. What is the maximum speed with which the ball can be moved?