A particle moves along the side AB, BC and CD of a square of side 25m with a velocity of 15ms-1. Its average velocity is
Correct answer: D. 5ms-1
- A. 15ms-1
- B. 7.5ms-1
- C. 10ms-1
- D. 5ms-1
Explanation
The average velocity is defined as the total displacement divided by the total time taken. In this problem, the particle moves along three sides of a square, with each side being 25m long. Therefore, the total displacement from starting point A to ending point D is the straight-line distance between these points, which is equivalent to the side of the square, 25m.The total distance traveled is 75m (25m + 25m + 25m), and the time taken is calculated as total distance divided by speed: 75m / 15ms-1 = 5s. Thus, the average velocity is 25m / 5s = 5ms-1.Options A, B, and C are incorrect because they do not correctly apply the formula for average velocity, which involves the total displacement, not the total distance traveled.
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