A body is traveling with a constant acceleration of 10 ms-2. If S1 is the distance traveled in 1st second and S2 is the distance traveled in 2nd second, which of the following shows a correct relation between S1 and S2.
Correct answer: C. S2 = 3S1
- A. S1 = S2
- B. S1 = 3S2
- C. S2 = 3S1
- D. 2S2 = 3S1
Explanation
To find the distance traveled in a specific second under constant acceleration, use the formula for the distance covered in the nth second: Sn = u + (a/2)(2n - 1), where u is the initial velocity, and a is the acceleration. Assuming the body starts from rest (u = 0) and has an acceleration of 10 ms-2: S1 = (10/2)(2*1 - 1) = 5 m S2 = (10/2)(2*2 - 1) = 15 m Thus, S2 = 3S1. This confirms Option C is correct. The other options present incorrect relationships based on the formula.
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