A moving coil galvanometer of resistance 100? gives half scale deflection for a current of 20mA. What will be the potential difference across it ?
Correct answer: C. 2 volt
- A. 4 volt
- B. 5 volt
- C. 2 volt
- D. 0.4 volt
Explanation
Using Ohm's law, the potential difference is V = IR = (0.020 A)(100 Ω) = 2.0 V. The half-scale deflection does not alter this calculation because the stated current is the current through the galvanometer. The likely wrong choice is d, caused by treating 20 mA as 0.20 A instead of 0.020 A.
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