A metal X on heating in nitrogen gives Y. Y on treatment with H2O gives a colourless gas which when passed through sodium hypochlorite liberates N2 gas. The compound Y is:
Correct answer: B. Mg3N2
- A. Mg(NO3)2
- B. Mg3N2
- C. NH3
- D. MgO
Explanation
The correct answer is Mg3N2. When magnesium (X) is heated in nitrogen, it forms magnesium nitride (Y). The chemical reaction is as follows: 3Mg + N2 → Mg3N2. When magnesium nitride (Y) is treated with water, it reacts to produce magnesium hydroxide and ammonia: Mg3N2 + 6H2O → 3Mg(OH)2 + 2NH3. The ammonia, being a colorless gas, reacts with sodium hypochlorite to release nitrogen gas: 2NH3 + 3NaClO → N2 + 3NaCl + 3H2O. Other options, such as magnesium nitrate (Mg(NO3)2), ammonia (NH3), and magnesium oxide (MgO), do not fit the series of reactions described in the question.
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The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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