A metal M readily forms it sulphates MSO4 which is water soluble. It forms its oxides MO which becomes inert on heating. It forms an insoluble hydroxide M(OH)2 which is soluble in NaOH solution. Then M is:
Correct answer: D. Be
- A. Mg
- B. Ba
- C. Ca
- D. Be
Explanation
Beryllium (Be) is the correct metal in this scenario. Beryllium sulfate (BeSO4) is water-soluble due to its high solvation energy, unlike other alkaline earth metal sulfates. Beryllium oxide (BeO) becomes inert upon heating, and beryllium hydroxide (Be(OH)2) is insoluble in water but dissolves in NaOH, forming sodium beryllate (Na2BeO2). The unique properties of beryllium match the described characteristics of metal M. The other options do not align with all the criteria provided in the question.
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The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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