A mass 'm' is hanging on an inextensible string to make a simple pendulum of time period "T". If the mass becomes '3 m', then the time period of the simple pendulum will be
Correct answer: B. T
- A. T/3
- B. T
- C. 3T
- D. √3T
Explanation
The time period of a simple pendulum is given by the formula T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. This formula shows that the time period is independent of the mass of the pendulum. Therefore, even if the mass changes from 'm' to '3m', the time period remains the same, which is T. Option B is correct as it correctly identifies that the time period does not change. Options A, C, and D are incorrect because they suggest that mass affects the time period, which it does not.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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