A is 2 years older than B who is twice as old as C. If A is 10, how old is C?
Correct answer: B. 4
- A. 3
- B. 4
- C. 5
- D. 6
Explanation
To solve the problem, define the relationships: Let C be x years old. Then B is 2x years old. If A is 2 years older than B, A's age is 2x + 2. We know A is 10, so 2x + 2 = 10. Solving for x gives 2x = 8, thus x = 4. Therefore, C is 4 years old. This makes Option B correct. Other options do not satisfy all given conditions: Option A results in A being younger than 10, Option C results in A being older, and Option D results in A being much older.
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Logical problems present several conditions about people, objects, events or choices and require their possible arrangements to be tested. They cover constraint-based reasoning, rankings, matching, grouping, scheduling and elimination, with attention to the difference between a complete solution and a possibility that merely satisfies one condition.
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