A gas expands 0.25 m3 at a constant pressure of 103 N/m2. The work done is:
Correct answer: B. 250J
- A. 2.5 ergs
- B. 250J
- C. 300J
- D. 150J
Explanation
The work done by a gas during expansion can be calculated using the formula: Work = Pressure × Change in Volume Given: Pressure = 103 N/m² Change in Volume = 0.25 m³ Work = (103 N/m²) × (0.25 m³) Work = 250 Nm = 250 J So, the correct answer is 250J.
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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