A flow of 107 electron per second in a conductor constitutes a current of
Correct answer: C. 1.6 x 10^-12 A
- A. 1.6 x 10^-26 A
- B. 1.6 x 10^12 A
- C. 1.6 x 10^-12 A
- D. 107 A
Explanation
Q=10⁷×1.6×10−19 which is flowing per second in a conducting wire hence I=1. 6×10−12A
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