A cylist ridding at a speed of 5m/sec braked with uniform decceleration and stopped in 3m. The acceleration is:
Correct answer: D. -4.16m/sec2
- A. 2.16 m/s2
- B. -2.16 m/s2
- C. 4.16 m/s2
- D. -4.16m/sec2
Explanation
Option D is correct.Given data:final velocity= 0 m/s , Initial velocity= 5 m/s , Displacement =3 mFind out=uniform decceleration =?Solution:To solve this, we can use the following kinematic equation:v² = u² + 2as where:v is the final velocity (0 m/s)u is the initial velocity (5 m/s)a is the accelerations is the displacement (3 m)Plugging in the values, we get:0² = 5² + 2a(3)-125 = 6aa = -25/6 = -4.16 m/s²Therefore, the acceleration of the cyclist is -4.16 m/s². The negative sign indicates that the acceleration is in the direction opposite to the direction of motion, which means that the cyclist is decelerating.
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