A cricket ball is hit so that it travels straight up in air and its acquires 3 seconds to each ball to reach the maximum height. Its initial velocity is:
Correct answer: C. 29.4ms-1
- A. 10ms-1
- B. 15ms-1
- C. 29.4ms-1
- D. 12.2ms-1
Explanation
To determine the initial velocity of the cricket ball, we use the equation of motion: v = u + at. At the maximum height, the final velocity v is 0 m/s. Given that the ball takes 3 seconds to reach this height and the acceleration due to gravity a is -9.8ms-2, we can rearrange the equation to find the initial velocity u:0 = u + (-9.8ms-2)(3s)u = 9.8ms-2 * 3s = 29.4ms-1Thus, the initial velocity is 29.4ms-1. Other options are incorrect as they do not satisfy the equation with the given values.
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