A current of 4.4 amperes is following in a write. How many electrons pass a given point in the wire in one second, if the charge on an electron is 1.6 x 10^-19 Coulomb?
Correct answer: B. 2.75 x 10^19 electrons
- A. 1.5 x 10^19 electrons
- B. 2.75 x 10^19 electrons
- C. 3.25 x 10^19 electrons
- D. 2.75 x 10^15 electrons
- E. 3.25 x 10^17 electrons
Explanation
I=4.4A e=1.610-19C (charge on one electron)t=1sn=? (no of electrons)Solution: I=q/t As, q=ne I=ne/tRearranging n=(It)e n=(4.41)1.610-19C =2.751019C electrons Result: n = 2.751019C electrons
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