A clock is 10 minutes fast at 9 AM and gains 2 minutes every hour. What will be the time on the faulty clock at 3 PM?
Correct answer: C. 3:22 PM
- A. 3:20 PM
- B. 3:10 PM
- C. 3:22 PM
- D. 3:15 PM
Explanation
The clock is 10 minutes fast at 9 AM. From 9 AM to 3 PM, there are 6 hours. The clock gains an additional 2 minutes per hour, for a total of 12 minutes gained over 6 hours. Adding the initial 10-minute lead, the clock is a total of 22 minutes fast by 3 PM. Therefore, the time on the faulty clock will be 3:22 PM. Other options don't correctly account for the total time gained by the clock.
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Logical problems present several conditions about people, objects, events or choices and require their possible arrangements to be tested. They cover constraint-based reasoning, rankings, matching, grouping, scheduling and elimination, with attention to the difference between a complete solution and a possibility that merely satisfies one condition.
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