A charge of 2C experiences a force of 2000N in a uniform electric field. In this field, the potential difference between two points separated by a distance of 1cm is:
Correct answer: C. 10V
- A. 2V
- B. 5V
- C. 10V
- D. 20V
Explanation
First, find the electric field strength: E = F/q = 2000 N / 2 C = 1000 N/C. The potential difference is V = Ed = (1000 N/C) × (0.01 m) = 10 V.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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