A 5µF capacitor has a potential difference across its plates of 200 volts. The charge on the capacitor is:
Correct answer: B. 10⁻³ C
- A. 2.5×10⁻³ C
- B. 10⁻³ C
- C. 10³ C
- D. 4×10³ C
Explanation
The charge (Q) stored on a capacitor is given by the formula Q = CV. Q = (5 × 10⁻⁶ F) × (200 V) = 1000 × 10⁻⁶ C = 10⁻³ C.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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