A car of mass 1000kg is moving with speed 72km/h in a circular track of radius 100m. The centripetal force acting on it is
Correct answer: D. 4000N
- A. 4N
- B. 400N
- C. 40N
- D. 4000N
Explanation
The explanation is as follows To calculate the centripetal force acting on a car of mass 1000kg moving with speed 72km/h in a circular track of radius 100m, we can use the following formula: F_c = mv^2 / r where: Fc is the centripetal force in Newtons (N) m is the mass of the object in kilograms (kg) v is the velocity of the object in meters per second (m/s) r is the radius of the circle in meters (m) First, we need to convert the car's speed from kilometers per hour to meters per second. We can do this by multiplying by 5/18: v = 72 km/h * 5/18 m/s/km = 20 m/s Now, we can plug in the values for m, v, and r into the formula for centripetal force: F_c = (1000 kg)(20 m/s)^2 / 100 m = 4000 N Therefore, the centripetal force acting on the car is 4000 N.
Last updated
About Newton's Laws of Motion
Newton’s laws explain inertia, the relation between net force and acceleration, and action-reaction pairs. Questions involve free-body diagrams, balanced and unbalanced forces, F = ma, force as the rate of change of momentum, and identifying genuine third-law pairs, which act on different bodies.
Practise Force and Motion
1,416 free Force and Motion MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
1st law of motion gives the definition of _________________________?
3rd law of motion explains______________________?
A 60kg man in a lift which is moving upward with an acceleration of 4.8m/s² will have an apparent weight of
A body in equilibrium must not have:
A body is having weight 20 N, when the elevator is descended with a = 0.1 ms-2, then the value of tension 'T' is: