A 60kg man in a lift which is moving upward with an acceleration of 4.8m/s² will have an apparent weight of
Correct answer: B. 294 N
- A. 588 N
- B. 294 N
- C. 58.8 N
- D. 882 N
Explanation
To find the apparent weight, we subtract the force due to acceleration (\(ma\)) from the actual weight (\(mg\)). Substituting the given values, we get 294N.
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