A brivalent metal has the equivalent weighr of 12. The molecular weight to its oxide will be_______?
Correct answer: D. 40
- A. 24
- B. 32
- C. 36
- D. 40
Explanation
For a bivalent metal, equivalent weight = atomic weight ÷ 2, so its atomic weight is 12 × 2 = 24. Its oxide is MO, therefore molecular weight = 24 + 16 = 40 g mol^-1. The common mistake is choosing 24 by reporting the metal's atomic weight instead of the oxide's molecular weight.
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About Reactions of Group II Elements
Group II reactions cover the behaviour of beryllium, magnesium, calcium, strontium and barium with water, oxygen, halogens, acids and nitrogen. The trends in reactivity, hydroxide solubility and basicity, along with the thermal decomposition of carbonates and nitrates, depend on increasing atomic size down the group.
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