A bar magnet has a magnetic moment 200 Am2. The magnet is suspended in a magnetic field of 0.30 NA-1m-1. The torque required to rotate the magnet from its equilibrium position at an angle of 30˚ will be:
Correct answer: A. 30Nm
- A. 30Nm
- B. 3073 Nm
- C. 60Nm
- D. 604Nm
Explanation
τ = MBsinθTorque = 200×0.30×sin30 = 30 Nm.
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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