A ball is thrown horizontally from the top of a cliff with a speed of 40 m/s. It hits the ground in 2 seconds. What is the distance from the cliff to the point at which the ball hits the ground?
Correct answer: C. 80 m
- A. 20 m
- B. 40 m
- C. 80 m
- D. 19.6 m
Explanation
When analyzing motion in two dimensions, it's crucial to separate the horizontal and vertical components. In this scenario, the ball is thrown horizontally with a speed of 40 m/s and hits the ground in 2 seconds. The horizontal distance traveled by the ball can be determined using:Horizontal distance = horizontal speed × timeSubstitute the values: 40 m/s × 2 s = 80 mTherefore, the distance from the cliff to the point where the ball hits the ground is 80 meters. Options A, B, and D are incorrect as they do not follow the correct formula and reasoning.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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