2.00 x 10^6 e passing through a conductor in 1 millisecond. Electric current through conductor is:
Correct answer: A. 3.2 x 10^-10 A
- A. 3.2 x 10^-10 A
- B. 32.0 x 10^-9 A
- C. 320 x 10^-10 A
- D. 0.320 x 10^-10
Explanation
Charge on an electron is 1.6x10-¹⁹CWhat will be the total charge on n number of electrons?In this case, n=2x10⁶ electrons E=neWhere e is charge on one electron And E is total charge =2x10⁶x1.6x10^-¹⁹ =3.2x10-¹⁹CNow we know:I=Q/t =3.2x10-¹³/1x10-³note:Convert milli sec into sec =3.2x10-¹⁰AA is the correct answer Charge on an electron is 1.6x10-¹⁹CWhat will be the total charge on n number of electrons?In this case, n=2x10⁶ electrons E=neWhere e is charge on one electron And E is total charge =2x10⁶x1.6x10^-¹⁹ =3.2x10-¹⁹CNow we know:I=Q/t =3.2x10-¹³/1x10-³note:Convert milli sec into sec =3.2x10-¹⁰AA is the correct answer Charge on an electron is 1.6x10-¹⁹CWhat will be the total charge on n number of electrons?In this case, n=2x10⁶ electrons E=neWhere e is charge on one electron And E is total charge =2x10⁶x1.6x10^-¹⁹ =3.2x10-¹⁹CNow we know:I=Q/t =3.2x10-¹³/1x10-³note:Convert milli sec into sec =3.2x10-¹⁰AA is the correct answer on an electron is =2x10^6x1.6x10^-19 milli sec into sec
Last updated
Related questions
A certain X-ray tube requires a current of 5mA at a voltage of 60kv. The rate of energy dissipation (in watts) is:
Kirchofrs current law (KM.) Is based upon law Of conservation of:
A total charge of 100C flows through a 12W bulb in a time of 50 second. What is the potential difference across the bulb during this time?
A 0.01A moving coil Galvanometer of 5 Ω resistance can be converted into a 0.2A ammeter by a resistance R with the Galvanometer when r is:
Four wires meet at a junction. The first carries 4A in to the junction, the second carries 5A out of the junction, and third carries 2A out of the junction. The fourth carries: