What is the current in a 2 x 10^6 ohms resistor having a potential difference of 6 x 10^3 volts?
Correct answer: C. 3 x 10^-3 A
- A. 1 x 10^-3 A
- B. 2 x 10^-3 A
- C. 3 x 10^-3 A
- D. 4 x 10^-3
Explanation
According to Ohm's Law V=IR Since V= 6x103 Volts R= 2 x 106 ohms Hence; I=V/R; I = 6x103 / 2x106 = 3x10-3 Ampere (so option C is the correct answer)
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