Free Periodic Properties and Trends MCQs with Answers
606 Periodic Properties and Trends MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
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606 questions · page 25 of 31
- A. Mendeleev's periodic law
- B. Newland's law of octaves
- C. Doberenier's triads
- D. Lothar Meyer's classification
- E. Modern periodic law
Explanation: The modern Periodic law can be stated as: "The physical and chemical properties of the elements are periodic functions of their atomic…
Correct answer: Modern periodic law- A. They belong to 18th group of modern periodic table
- B. Except Rn, all the remaining atoms are present in the air.
- C. These elements belong to 17th group in IUPAC system.
- D. These are highly reactive elements.
- E. None of the above
Explanation: According to the periodic table, noble gases lie in 18th group also known as 0 group. So, option A is correct.
Correct answer: They belong to 18th group of modern periodic table- A. Option A
- B. Option B
- C. Option C
- D. Option D
- E. Option E
Explanation: CH3 is an ortho-para (2,4,6) directing group which means the incoming group attaches to the ortho or para position.
Correct answer: Option D- A. S block element
- B. P block element
- C. D block element
- D. Noble gases
Explanation: At the end of the periodic table noble gases are found as shown below:
Correct answer: Noble gases- A. CO2
- B. CI2
- C. O2
- D. N2
- E. Na
Explanation: Carbon dioxide (CO2) and Clorine are the gas that reacts with calcium oxide (CaO) but does not react with sodium bicarbonate (NaHCO3).
Correct answer: Na- A. Decreases
- B. Increases
- C. I st increase and then decrease
- D. I st decrease and then increase
Explanation: Ionic radius decreases moving from left to right across a row or period.
Correct answer: Decreases- A. decreases down the groups
- B. increases down the groups
- C. remains same across the periods
- D. increases across the periods
Explanation: As we go down the group, the size of atoms increases. Due to this the nuclear force of attraction on the electrons in the valence shell…
Correct answer: increases down the groups- A. 2H2O + NOCI+Cl2
- B. H2 + NOCI+ 2HOCI
- C. H2O+ NOCI+ 2HCl
- D. 2H2O+NOCI+ 2Cl
Explanation: HNO3 and HCL mix in the ratio of 1:3 to give aqua regia that is 2H2O + NOCl + 2Cl.
Correct answer: 2H2O+NOCI+ 2Cl- A. Na2B2O7.10H2O
- B. Na2B4O7 . H2O
- C. Na2B4O7 . 10 H2O
- D. Na2B2O5 . 10 H2O
Explanation: The chemical formula of Tincal is Na2B4O7 10H2O This requires just a factual recall.
Correct answer: Na2B4O7 . 10 H2O- A. I-A, V-A and VIll-A
- B. I-A, IV A and Vl-A
- C. I-A, II-A and VIl-A
- D. I-A, IV-A and VIl-A
Explanation: Hydrogen resembles the elements of group of I A as it has one valence electron and can lose and electron to form a cation, it also…
Correct answer: I-A, IV-A and VIl-A- A. Down the Group
- B. Along period
- C. Along d- block
- D. All of these
Explanation: The covalent character 'decreases in groups' as we go from top to bottom.
Correct answer: Down the Group- A. All blocks
- B. The p-block elements
- C. The d and f block elements
- D. None of the blocks
Explanation: In the case of d-block elements due to the presence of electrons at d orbitals, is closer to the outermost shell of the metal.
Correct answer: The d and f block elements- A. The number of electrons used in bonding
- B. The number of orbits holding electrons
- C. The (proton) atomic number
- D. The relative atomic number
Explanation: A. Lithium uses 1 electron in bonding, Beryllium 2, Boron 3, Carbon 4, Nitrogen 3, Oxygen 2, Fluorine 1 and Ne being a noble gas doesn't…
Correct answer: The number of electrons used in bonding- A. An element which has high electronegativity always has high electron gain enthalpy.
- B. Electron gain enthalpy is the property of an isolated atom.
- C. Electronegativity is the property of bonded atoms.
- D. Both electronegativity and electron gain enthalpy are usually directly related to nuclear charge and inversely related to atomic size.
Explanation: Option A is the correct answer because it incorrectly states that high electronegativity always corresponds to high electron gain…
Correct answer: An element which has high electronegativity always has high electron gain enthalpy.- A. Generally, the reducing character of elements increases across a period.
- B. Generally, the oxidizing character of elements increases across a period.
- C. Generally, the basic character of oxides decreases down a group.
- D. All are correct.
Explanation: The correct answer is Option B: 'Generally, the oxidizing character of elements increases across a period.' This is because as you move…
Correct answer: Generally, the oxidizing character of elements increases across a period.- A. IE1 of Li > IE1 of Be
- B. IE1 of Be > IE1 of B
- C. IE1 of Li < IE1 of Ca
- D. IE1 of He > IE1 of Ne
Explanation: The incorrect statement is Option A: IE1 of Li > IE1 of Be. This is incorrect because ionization energy increases across a period from…
Correct answer: IE1 of Li > IE1 of Be- A. Number of electrons
- B. Atomic number
- C. Number of valence electrons
- D. Electronic configurations
Explanation: The correct answer is that elements in the same vertical group of the periodic table have the same number of valence electrons.
Correct answer: Number of valence electrons- A. The element with the highest ionization energy (IE) belongs to group 18.
- B. In each period, the element with the lowest ionization energy belongs to group 1.
- C. In each period, the element with the highest ionization energy is a noble gas.
- D. In the second period, as we move from left to right, ionization energy increases regularly.
Explanation: The correct answer is Option D. While moving across a period from left to right, the general trend is an increase in ionization energy due…
Correct answer: In the second period, as we move from left to right, ionization energy increases regularly.- A. A: F > Cl > O > S
- B. B: S > Cl > O > F
- C. C: F > O > Cl > S
- D. D: Cl > F > O > S
Explanation: The correct order of increasing electronegativity is F > O > Cl > S. Electronegativity increases across a period from left to right and…
Correct answer: C: F > O > Cl > S- A. Among halogens, oxidizing behavior increases down the group
- B. Among alkali metals, reducing character increases down the group
- C. Fluorine is the most electronegative element
- D. Lithium is the hardest metal among alkali metals.
Explanation: The correct answer is Option A. In the halogen group, oxidizing behavior decreases down the group because the elements become less…
Correct answer: Among halogens, oxidizing behavior increases down the group