You have three capacitors, each of 2 µC. In which of the following combinations of the three capacitors, the resultant capacitance is 3µC?
Correct answer: B. Two capacitors are in series, one in parallel
- A. All three capacitors in series
- B. Two capacitors are in series, one in parallel
- C. Two capacitors are in parallel, one in series
- D. All three capacitors in parallel
Explanation
b) Two capacitors are in series, one in parallel: Let's say C_a and C_b are the two capacitors in series, and C_c is the capacitor in parallel. The total capacitance (C_total) in this combination is given by:1 / C_total = 1 / (C_a + C_b) +C_cSubstituting the values:1 / C_total = (1 /2 µC + 1/2µC) + 2 µC= 4/4 µC + 2 µC= 3 µCC_total = 3µC The total capacitance when two capacitors are in series and one in parallel is 3 µC so this option is correct.
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