With 21 V applied, if R1 = 5 ohms, R2 = 35 ohms, and R3 = 14 ohms, what is the current of R2 if R1 is series connected with parallel circuit R2 and R3?
Correct answer: B. 400 mA
- A. 200 mA
- B. 400 mA
- C. 600 mA
- D. 800 mA
Explanation
R2 and R3 have an equivalent resistance of 35 || 14 = 10 Ω, giving a total resistance of 15 Ω and total current of 1.4 A. The parallel branch voltage is 14 V, so the R2 current is 14/35 = 0.4 A, or 400 mA.
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