Which two or more of the following actions would increase the energy stored in a parallel plate capacitor when a constant potential difference is applied across the plates:
Correct answer: C. Increasing the area of the plates & decreasing the separation between the plates & inserting a dielectric between the plates
- A. Decreasing the area of the plates & decreasing the separation between the plates
- B. Decreasing the area of the plates & increasing the separation between the plates & inserting a dielectric between the plates
- C. Increasing the area of the plates & decreasing the separation between the plates & inserting a dielectric between the plates
- D. Increasing the area of the plates & increasing the separation between the plates
Explanation
The energy stored by a parallel plate capacitor depends upon the area of the plates, the distance between the plates, and the presence of dielectric between the plates. The energy stored will increase by increasing the Aaea of the plates, decreasing the distance between them, and by placing a dielectric between the plates.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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