Which one of the following is oxidation state of carbon in C12H22O11
Correct answer: A. 0
- A. 0
- B. -6
- C. +6
- D. 12
Explanation
To determine the oxidation state of carbon in a molecule, consider the following:Oxygen: Oxygen typically has an oxidation state of -2, except in rare cases involving highly electronegative elements like fluorine.Hydrogen: Hydrogen usually has an oxidation state of +1, except in metal hydrides (e.g., NaH) where it's -1.Now, let's assign tentative oxidation states to carbon (x) and balance the charges in the molecule:C₁₂H₂₂O₁₁: 12x + 22(+1) + 11(-2) = 0 (neutral molecule)Solving for x:12x - 22 + 22 = 012x = 0x = 0Therefore, the oxidation state of carbon in C₁₂H₂₂O₁₁ is 0.
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