Which one of the following combinations of radioactive decay results in the formation of an isotope of the original nuclide?
Correct answer: B. α and two β
- A. α and β
- B. α and two β
- C. Two α and β
- D. α and four β
Explanation
The emission of α-particle (each reducing Z by 2 and A by 4) in addition to two β-particles (which increase Z by 2 without changing A) would result in the formation of an isotope of the original nuclide because the net change in Z and A would be such that it corresponds to the same element as the original nuclide, just with a different isotope.
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