Which of the following reaction takes place when alkyl halide react with KOH in water?

Explanation

Correct option is A.When an alkyl halide (haloalkane) reacts with KOH (potassium hydroxide) in water, the reaction that typically takes place is substitution reaction.This reaction is known as the nucleophilic substitution reaction. The halogen atom in the alkyl halide is replaced by the hydroxide ion (OH-) from the KOH. The general reaction can be represented as follows:R-X + KOH (aq) -> R-OH + KXWhere:R-X represents the alkyl halide (e.g., CH3-Cl, CH3-Br, CH3-I, etc.).KOH (aq) is the potassium hydroxide dissolved in water.R-OH represents the alcohol formed as a result of the substitution reaction.KX represents the potassium halide (e.g., KCl, KBr, KI) produced as a byproduct.In this reaction, the nucleophile (OH-) attacks the electrophilic carbon of the alkyl halide, and the halogen is displaced, leading to the formation of an alcohol.