Which of the following is a molecule formed in a metabolic pathway by the equal splitting of a phosphorylated hexose into two halves?
Correct answer: D. Triose phosphate
- A. Acetyle coenzyme A
- B. Ribulose-1,5-bisphosphate
- C. Fructose 1, 6-bisphosphate
- D. Triose phosphate
Explanation
Yes, the correct answer is triose phosphate. In the process of glycolysis, a six-carbon sugar called glucose is first converted into a phosphorylated hexose, fructose-1,6-bisphosphate. This compound is then split equally into two three-carbon molecules-glyceraldehyde-3-phosphate (G3P) and dihydroxyacetone phosphate (DHAP). Both of these are known as triose phosphates. This step marks the transition from a six-carbon to a three-carbon stage in glycolysis, allowing energy extraction to continue in later steps of the metabolic pathway.
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About Bioenergetics
Cellular respiration explains how cells release energy from glucose through glycolysis, the link reaction, Krebs cycle and electron transport chain. It includes ATP production, substrate-level and oxidative phosphorylation, aerobic versus anaerobic respiration, and the roles of mitochondria, oxygen and fermentation in energy transfer.
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