Which of the following expression is constant for a freely falling body?
Correct answer: C. mgh + ½ mv²
- A. mgh + mv2
- B. mgh - mv²
- C. mgh + ½ mv²
- D. mgh - ½ mv²
Explanation
When a body falls freely, its kinetic energy increases while its potential energy decreases. But the total mechanical energy is conserved during the free fall.Hence E = P.E + K.E is constant.E = mgh + ½mv².
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Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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