Which of the following compounds has the same molecular and empirical formula?
Correct answer: C. C₁₂H₂₂O₁₁
- A. C₆H₁₂O₆
- B. C₂H₆O
- C. C₁₂H₂₂O₁₁
- D. C₂H₄O
Explanation
A compound's molecular and empirical formulas are the same if the subscripts in the molecular formula cannot be simplified by a common divisor. The subscripts in C₁₂H₂₂O₁₁ (sucrose) have no common factor and cannot be reduced.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
Practise Fundamental Concepts of Chemistry
894 free Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Fundamental Concepts of Chemistry questions
All of the following statements are incorrect for 20 moles of water except:
0.5 moles of H₂O are formed when one gram of H₂ reacts with how many grams of oxygen?
The sole products of the complete combustion of a simple hydrocarbon are:
Which of the following statements about alcohol oxidation is incorrect?
On complete combustion, a 44-gram sample of a compound gives 88 grams of CO₂ and 36 grams of H₂O. The molecular formula of the compound may be:
The empirical formula and molecular mass of a compound are CH₂O and 180 g/mol respectively. The molecular formula of the compound is: