Asked in ETEA MDCAT 2012 2012Moderate

Which arrangement of the photons is in their decreasing energy?

Correct answer: B. x rays > u.v. > visible > i.r.

  • A. x rays > i.r. > u.v. > visible
  • B. x rays > u.v. > visible > i.r.
  • C. u.v. > x rays > visible > i.r.
  • D. i.r. > visible > x rays > u.v.

Explanation

In the electromagnetic spectrum, the energy of photons is inversely proportional to their wavelength. Thus, shorter wavelengths correspond to higher energy. X-rays have the shortest wavelength and highest energy, followed by ultraviolet (u.v.) light, then visible light, and finally infrared (i.r.) light, which has the longest wavelength and lowest energy. Option B correctly reflects this order: x-rays > u.v. > visible > i.r.Other options are incorrect because they do not correctly arrange the types of radiation by decreasing energy according to their wavelength.

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About Electromagnetic Waves

Electromagnetic waves consist of mutually perpendicular, oscillating electric and magnetic fields that also remain perpendicular to the direction of propagation. They travel through vacuum at the speed of light and include radio waves, microwaves, infrared, visible, ultraviolet, X-rays and gamma rays. Unlike mechanical waves, they do not require a material medium.

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