Asked in Premeth past paper pool — BiologyModerate

When two heterozygotes (AaBb) of completely dominant traits are crossed, then the probability of appearance of AABB genotype would be:

Correct answer: A. 1/16

  • A. 1/16
  • B. 3/16
  • C. 6/16
  • D. 9/16

Explanation

When two heterozygotes (AaBb) for completely dominant traits are crossed, the probability of an offspring having the AABB genotype is 1/16. This is because each parent has a 1/2 chance of contributing an 'A' allele and a 1/2 chance of contributing a 'B' allele. To get AABB, you need both parents to contribute 'A' and 'B', so (1/2)(1/2)(1/2)*(1/2) = 1/16. So option A is correct. B,C and D gives wrong probability.

Last updated

About Mendel's Laws of Inheritance

Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.

Practise Inheritance

1,238 free Inheritance MCQs from Biology, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Biology questions like this

Biology is on 6 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions