When two heterozygotes (AaBb) of completely dominant traits are crossed, then the probability of appearance of AABB genotype would be:
Correct answer: A. 1/16
- A. 1/16
- B. 3/16
- C. 6/16
- D. 9/16
Explanation
When two heterozygotes (AaBb) for completely dominant traits are crossed, the probability of an offspring having the AABB genotype is 1/16. This is because each parent has a 1/2 chance of contributing an 'A' allele and a 1/2 chance of contributing a 'B' allele. To get AABB, you need both parents to contribute 'A' and 'B', so (1/2)(1/2)(1/2)*(1/2) = 1/16. So option A is correct. B,C and D gives wrong probability.
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Mendelian inheritance explains how alleles separate into gametes and assort during reproduction, producing predictable genotype and phenotype ratios. Questions cover dominance, recessiveness, homozygous and heterozygous conditions, the laws of segregation and independent assortment, monohybrid and dihybrid crosses, test crosses and the limits caused by linked genes.
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