When the change in concentration is 6 x 10^-4 mol dm-3 and time for that change is 10 seconds, the rate of reaction will be:
Correct answer: D. 6 x 10^-5 mol dm-3 sec-1
- A. 6 x 10^-3mol dm-3 sec-1
- B. 6 x 10^-4 mol dm-3 sec-1
- C. 6 x 10^-2 mol dm-3 sec-1
- D. 6 x 10^-5 mol dm-3 sec-1
Explanation
πππ‘π ππ πππππ‘πππ = ΞπΆ/π‘ = (6 Γ 10β4 )/10 = 6 Γ 10β5πππππβ3π ππβ1 Given: Change in concentration = 6 x 10^(-4) mol dm^(-3) Time = 10 secondsRate of reaction = Change in concentration / TimeSubstituting the given values:Rate of reaction = (6 x 10^(-4) mol dm^(-3)) / 10 secondsSimplifying:Rate of reaction = 6 x 10^(-5) mol dm^(-3) sec^(-1)Among the given options, the closest value to the calculated rate is Option D: 6 x 10^(-5) mol dm^(-3) sec^(-1).Therefore, the rate of reaction will be approximately 6 x 10^(-5) mol dm^(-3) sec^(-1).
This question appeared on the UHS MDCAT 2015 paper, which you can sit online with every answer explained.
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About Rate of Reaction
Reaction rate measures the change in concentration of a reactant or product per unit time. Questions connect rate with concentration, temperature, pressure, surface area, catalysts and nature of reactants, and may involve rate laws, reaction order, activation energy and collision theory. Rate describes speed, whereas equilibrium describes the final balance of opposing reactions.
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